Can the quadratic polynomial x2+kx+k
WebClick here👆to get an answer to your question ️ If 12 is a root of the equation x^2 + kx - 54 = 0 , then find the value of k. ... ∴ 2 1 is a root of the quadratic equation It must satisfy the quadratic equation x 2 + k x ... If α, β are the zeros of quadratic polynomial f (x) = x 2 ... WebSolution: Given, the quadratic polynomial is x² + kx + k We have to find the zeros of the polynomial We know that, if 𝛼 and ꞵ are the zeroes of a polynomial ax^2 + bx + c, then …
Can the quadratic polynomial x2+kx+k
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WebThe only value of k for which the quadratic polynomial kx2 + x + k has 1 2 (D) Short Answer Questions 1 x 2, and verify the 6 relation between the coefficients and the zeroes of the polynomial. Sample Question 1:Find the zeroes of the polynomial x2 + Solution : x2 + 1 1 1 x 2= (6x2 + x 12) = [6x2 + 9x 8x 12] 6 6 6 WebApr 25, 2024 · The zeroes of the quadratic polynomial x 2 + kx + k, k ≠ 0, (A) cannot both be positive (B) cannot both be negative (C) are always unequal (D) are always equal …
WebChoose the correct answer from the given four options: The number of polynomials having zeroes as –2 and 5 is. (A) 1. (B) 2. (C) 3. (D) more than 3. Answer: Quadratic polynomial having zeroes α and β is given by k[x2 - (α + β)x + αβ]. So, the quadratic polynomial having zeroes −2 and 5 is given by. WebJul 9, 2016 · Since a quadratic equations roots are in fact its x intercepts, and a perfect square trinomial will have 2 equal, or 1 distinct solution, the vertex lies on the x axis. We can set the discriminant to 0 and solve: k2 −(4 × 1 ×36) = 0 k2 −144 = 0 (k +12)(k −12) = 0 k = ± 12 So, k can either be 12 or −12. Hopefully this helps! Answer link
WebJul 20, 2024 · Let the given polynomial be, f ( x) = x2 + kx + k For f ( x) to have equal roots, its discriminant must be zero. b2 – 4 ac = 0 ( k) 2 – 4 (1) ( k) = 0 k2 – 4 k = 0 k ( k – 4) = 0 k... WebApr 5, 2024 · Complete step by step answer: We know that sridhar acharya's formula for quadratic equation is. x = − b ± D 2 a. where discriminant D is given by. D = b 2 − 4 a c. …
Web(ii) If the graph of a polynomial intersects the x-axis at only one point, it cannot be a quadratic polynomial. (iii) If the graph of a polynomial intersects the x-axis at exactly two points, it need not be a quadratic polynomial. (iv) The only value of k for which the quadratic polynomial kx 2 + x + k has equal zeros is 1/2
WebOct 22, 2024 · If one of the zeroes of the quadratic polynomial x 2 + 3x + k is 2, then the value of k is (a) 10 (b) – 10 (c) – 7 (d) – 2. Answer. B. ... The zeros of the quadratic polynomial x 2 +kx+k,k≠0 (a) both cannot be positive (b) both cannot be negative (c) are always equal (d) are always unequal. Answer. A. blood tests broomfield hospital chelmsfordWebAs it k i... 1 Can the quadratic polynomial x2 + kx +k have equal zeroes for some odd integer k greater than 1 Ex 2.2 Class 10 NCERT exemplar*k has no value. blood test scalp acneWebQuestion 8 The zeros of the quadratic polynomial x2+kx + k where k ≠ 0 A cannot both be positive B cannot both be negative C are always unequal D are always equal. Login. … free directional sign templateWebSolution. Find the value of k. Given: One zero of p x = 4 x 2 - 8 x k - 9 is negative to the other. let α be the one root of the quadratic equation. So, the other root will be - α. We know that for the quadratic equation a x 2 + b x + c sum of the roots is given by - b a. Thus, sum of the roots of the given quadratic equation = 8 k 4. blood tests by postWebWrite your answers from least to greatest, separates by commas. x^(2)+kx-19. ANALYZE Find all values of k so that the polynomial can be factored using integers. Write your answers from least to greatest, separates by commas. x^(2)+kx-19 ... if α, β are the roots of a quadratic polynomial then polynomial will be x 2 ... blood test scammerWebWhat is the value of k, given the quadratic equation 2x²+kx+3=0? Noting that the Quadratic equation will equal only when Discriminant (D)=±b² - 4ac=0 and with the comparison of general form of quadratic equation 2x² + kx + 3 = 0, we get, a=2, b=k, c=3. D= k² - 4 (2) (3) = 0 = k² - 24 = 0 = k² = 24 i.e, k= ±2√6 Hence, k= 2√6 , k= - 2√6 free direct input driverWebIf one of the zeroes of the quadratic polynomial (k - 1)x 2 + kx + 1 is -3, then the value of k is a) 4/3 b) -4/3 c) 2/3 d) -2/3 Correct answer is option 'A'. Can you explain this answer? Answers Vp Classes p (x) = (k - 1)x 2 + kx +1 One zero of polynomial is - 3 i.e. p (-3) = 0 ⇒ (k - 1) (-3) 2 + k (-3) + 1 = 0 ⇒ 9k - 9 - 3k + 1 = 0 ⇒ 6k - 8 = 0 free directions and maps