Webcot (θ) = 0 cot ( θ) = 0 Take the inverse cotangent of both sides of the equation to extract θ θ from inside the cotangent. θ = arccot(0) θ = arccot ( 0) Simplify the right side. Tap for more steps... θ = π 2 θ = π 2 The cotangent function is positive in the first and third quadrants. Web20 dec. 2024 · Find an answer to your question if cosectheta+cottheta=k then find value of cos theta in terms of k. manoj76 manoj76 20.12.2024 Math Secondary School answered If cosectheta+cottheta=k then find value of cos theta in terms of k See answer -1 Advertisement Advertisement

If x = tantheta + cottheta, y = costheta - sintheta , then - Toppr

Web22 mrt. 2024 · Ex 8.4, 1 - Chapter 8 Class 10 Introduction to Trignometry (Term 1) Last updated at March 22, 2024 by Teachoo. Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. Transcript. Show More. Next: Ex 8.4, 2 Important → Ask a doubt . Chapter 8 Class 10 Introduction to Trignometry; Web10 dec. 2024 · Write both equation in terms of sine and cosine functions only: x = cos(θ) sin(θ) + sin(θ) cos(θ); y = 1 cos(θ) − cos(θ) Make common denominators for both … shoppyland fust

Solve for θ: tanθ +cotθ = 2 - BYJU

Webcot (θ) = −1 cot ( θ) = - 1. Take the inverse cotangent of both sides of the equation to extract θ θ from inside the cotangent. θ = arccot(−1) θ = arccot ( - 1) Simplify the right … Web21 dec. 2024 · Correct Answer - B `tan^(-1) ((x cos theta)/(1 - x sin theta)) - cot^(-1) ((cos theta)/(x - sin theta))` `= tan^(-1) ((x cos theta)/(1 - x sin theta)) - tan^(-1) ((x ... Web22 okt. 2024 · Best answer LH S = (m + n) √mn. L H S = ( m + n) m n. Now, (m + n) = 2 cos θ and nm = (cos2 θ − sin2 θ) = cos2 θ(1 − tan2 θ). ( m + n) = 2 cos θ and n m = ( cos 2 θ - sin 2 θ) = cos 2 θ ( 1 - tan 2 θ). ∴ √mn = cos θ√1 − tan2 θ. ∴ m n = cos θ 1 - tan 2 θ. shoppyland ente